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Differential equations of \frac {dy} {dx}=f (x) dxdy = f (x) are very and easy to solve. to do it: Step 1. First we sides by dx dx to obtain. dy=f (x)~dx. dy = f (x) dx. Step 2. we take integral of sides to obtain. \begin {aligned} \int dy&=\int f (x)~dx\\ y+C'&=\int f (x)~dx
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If we plug in t= 0, C 0 = r k A k e k0 = r k A k; so A= r kC 0. concentration at tis given by equation C(t) = r k r kC 0 k e kt or, equivalently, C(t) = r.
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Question: (3 points) all apply to differential equation dydxβsin2 (x)y=cos2 (x)y+xdydxβsin2β‘ (x)y=cos2β‘ (x)y+x A. ODE B. PDE C. first order D. second order E. order F. linear G. a candidate for integrating factors J. Question.
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been solved! You'll get a detailed solution a subject expert you learn core concepts. Question: given differential equation is exact. If it is exact, solve it. (If it is not exact, enter NOT.) x dy dx = 4xex β y + 6x2. given differential equation is exact.
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questions and answers. x (dy/dx) = 8y.
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precise of variables and depends on context of application and required level of rigor
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Transcript. Ex , 8 given differential equation is and solve of π₯ ππ¦/ππ₯βπ¦+π₯π ππ(π¦/π₯)=0 Step 1: Find ππ¦/ππ₯ π π π/π π = y β x sin (π/π) Step 2: Put ππ¦/ππ₯ = F (x, y) and find F(πx, πy) F(x, y) = π¦/π₯ β sin (π¦/π₯) F(πx, πy) = ("π" π¦)/("π" π₯
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